Question

What is the probability of gamete AbC produced by a plant having genotype AaBbCc (If all the genes are situated on different chromosomes)?

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{1}{6}$
• D. $\frac{1}{8}$

Answer 1

The correct option is D $\frac{1}{8}$

The probability of formation of gamete AbC from the plant having genotype AaBbCc, mentioned that all genes are located on different chromosomes and there is no interaction while inheritance, which means that all the genes can be treated as inherited equally and then multiplying the individual frequencies, as stated-

Aa can form gametes A and a. So, the probability of A gene in a gamete is 1/2

Bb can form gametes B and b. So, the probability of b gene in a gamete is 1/2

Cc can form gametes C and c. So, the probability of C gene in a gamete is 1/2.

So probability for gamete with gene combination AbC = 1/2 x 1/2 x 1/2

= 1/8

So, the correct answer is '1/8'.