What is the probability of getting at least one six in a single throw of three unbiased dice?

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Solution

The correct option is D

The probability of getting no six is ${(\frac{5}{6})}^{3}$ = $\frac{125}{216}$

Hence the probability of getting at least one six is 1 - $\frac{125}{216}$ = $\frac{91}{216}$

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