Question

What is the probability of getting exactly two heads, when three coins tossed simultaneously?

Answer 1

Three coins are tossed simultaneously.

Possible outcomes $=\{HHH,HHT,HTH,HTT,TTT,TTH,THT,THH\}$

No. of total outcomes $=8$

Favourable outcomes $=\{HHT,HTH,THH\}$

No. of favourable outcomes $=3$

Therefore,

Probability of getting exactly two heads $=\frac{\text{No. of favourable outcomes}}{\text{No. of total outcomes}}=\frac{3}{8}$

Hence the probability of getting exactly two heads is $\frac{3}{8}$.