What is the probability of three coins falling all heads up when tossed simultaneously?

\frac{1}{2}

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\frac{1}{6}

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\frac{1}{8}

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\frac{7}{8}

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Solution

The correct option is C $\frac{1}{8}$
the probability of three coins falling all heads up when tossed simultaneously

$S = H H H, H H T, H T H, H T T, T H H, T H T, T T H, T T T, N = 8$

Therefore only in one condition the all heads comes up
therefore $P (E) = \frac{1}{8}$

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Similar questions

\frac{3}{8}

What is the probability of getting all heads or all tails, when three coins are tossed simultaneously?

Outcome	3 heads	2 heads	1 head	No head
Frequency	23	72	77	28

200

Outcome	$3 h e a d s$	$2 h e a d s$	$1 h e a d$	No head
Frequency	$23$	$72$	$77$	$28$

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