Question

What is the probability that an ordinary year has 53 Sundays ?

• A. $\frac{53}{365}$
• B. $\frac{1}{7}$
• C. $\frac{2}{7}$
• D. $\frac{48}{53}$

Answer 1

The correct option is B $\frac{1}{7}$

Ordinary year contains 365 days
$\therefore 52$ complete weeks and one day .
Possibilities for this one day are:
{Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday}
Total possibilities = $7$
favorable cases = $1$
$\therefore$ probability = $\frac{1}{7}$
Option B is correct.