Question

What is the probability that an ordinary year has 53 Tuesdays ?

Answer 1

An ordinary year has 365 days, i.e., 52 weeks and 1 day.

Now, 52 weeks have 52 Tuesdays and the remaining one day can be any of the 7 days.

$\therefore$ required probability = probability of this day being a Tuesday $=\frac{1}{7}$.