What is the probability that in a group of $^{'} N^{'}$ people, at least two of them have the same birthday.

Open in App

Solution

assuming the peoples in the group are born in a non leap year.
probability of two persons have the same birthdate $= \frac{1}{365} \times \frac{1}{365}$
probability that atleast two of the people having same birthday $= \frac{N c_{2}}{365 \times 365}$

Suggest Corrections

Similar questions

Q. The probability that in a group of

N

people at least two will have the same birthday is

Q. The probability that in a group of

N (< 365)

people at least two will have the same birthday, is________ .

The probability that in a group of 3 people, at least two will have the same birthday is:

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday ?

Q. The probability that out of

5

persons, all having birthday in March, at least two have the same birthday

Join BYJU'S Learning Program

What is the probability that in a group of ′N′ people, at least two of them have the same birthday.

assuming the peoples in the group are born in a non leap year. probability of two persons have the same birthdate =1365×1365 probability that atleast two of the people having same birthday =Nc2365×365

What is the probability that in a group of $^{'} N^{'}$ people, at least two of them have the same birthday.

assuming the peoples in the group are born in a non leap year.
probability of two persons have the same birthdate $= \frac{1}{365} \times \frac{1}{365}$
probability that atleast two of the people having same birthday $= \frac{N c_{2}}{365 \times 365}$