What is the quotient when $(x^{3} + 8)$ is divided by $(x^{2} - 2 x + 4)$ ?

x - 2

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x + 2

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x + 1

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x - 1

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Solution

The correct option is B $x + 2$
$x + 2$
$x^{2} - 2 x + 4$ $¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ x^{3} + 8$
$x^{3} - 2 x^{2} + 4 x$
$-$ $+$ $-$
-----------------------------
$2 x^{2} - 4 x + 8$
$2 x^{2} - 4 x + 8$
$-$ $+$ $-$
------------------------
$0$
Thus, we get the quotient as $x + 2$ and remainder as $0$ .
Hence, option B is correct.

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