What is the ratio between the number of graduates who had appeared for ES in 2010 and the number of graduates who appeared for CS in 2010?

13 : 21

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12 : 17

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12 : 19

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11 : 17

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11 : 19

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Solution

The correct option is C 12 : 19
Number of graduates who had appeared for ES in 2010 $= 60$
Number of graduates who had appeared for CS in 2010 $= 50 % o f 76000 = \frac{50}{100} \times 76000 = 38000$
$∴$ required ratio $= \frac{24000}{38000} = \frac{12}{19} o r 12 : 19$

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What is the ratio between the number of graduates who had appeared for ES in 2010 and the number of graduates who appeared for CS in 2010?

The correct option is C 12 : 19Number of graduates who had appeared for ES in 2010 =60 Number of graduates who had appeared for CS in 2010 =50% of 76000=50100×76000=38000 ∴ required ratio =2400038000=1219 or 12:19

The correct option is C 12 : 19
Number of graduates who had appeared for ES in 2010 $= 60$
Number of graduates who had appeared for CS in 2010 $= 50 % o f 76000 = \frac{50}{100} \times 76000 = 38000$
$∴$ required ratio $= \frac{24000}{38000} = \frac{12}{19} o r 12 : 19$