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Physical Properties

What is the r...

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What is the ratio of emperical formula mass to molecular formula mass of benzene

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Q. Empirical formula = C₂H₄O
n=2
(n=molecular mass ÷ emperical formula mass
Emperical formula mass = 44
Molecular mass = 88)
molecular formula = n × empirical formula
= 2 × C₂H₄O
= C₄H₈O₂
but the book answer is given that C₄H₈O
Which is correct ? If the book answer is correct , tell me how ?

A compound 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96 g. What are its emperical formula and molecular formula?

Q. A compound has the emperical formula

N a_{2} S O_{4}

. What is its molecular formula?

Q. The emperical formula of a compound is

C H_{2} O

and its molecular weight is 90. What is the molecular formula of the compound?

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