What is the ratio of the speeds of an electron in the first and second orbits of a hydrogen atom?

2 : 1

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1 : 2

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3 : 1

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1 : 1

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Solution

The correct option is A $2 : 1$ .
Speed of an electron in $n^{t h}$ orbit $= V_{0} \times \frac{1}{n}$
where $V_{0} =$ velocity in $1^{s t}$ orbit of hydrogen.
Speed in first orbit $= V_{0}$
Speed in second orbit $= \frac{V_{0}}{2}$
$∴$ Required ration $= 2 : 1$ .

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What is the ratio of the speeds of an electron in the first and second orbits of a hydrogen atom?

The correct option is A 2:1.Speed of an electron in nth orbit =V0×1nwhere V0= velocity in 1st orbit of hydrogen.Speed in first orbit=V0Speed in second orbit=V02∴ Required ration=2:1.

The correct option is A $2 : 1$ .
Speed of an electron in $n^{t h}$ orbit $= V_{0} \times \frac{1}{n}$
where $V_{0} =$ velocity in $1^{s t}$ orbit of hydrogen.
Speed in first orbit $= V_{0}$
Speed in second orbit $= \frac{V_{0}}{2}$
$∴$ Required ration $= 2 : 1$ .