What is the reaction involved in Holmes signal?

P H_{4} I (a q) + K O H (a q) \to K I (a q) + H_{2} O (a q) + P H_{3} (g)

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C a_{3} P_{2} + 6 H_{2} O \to 2 P H_{3} + 3 C a (O H)_{2} a n d C a C_{2} + 2 H_{2} O \to C_{2} H_{2} + C a (O H)_{2}

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C a_{3} P_{2} + 6 H C l \to 2 P H_{3} + 3 C a C l_{2}

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P_{4} + 3 N a O H + 3 H_{2} O \to P H_{3} + 3 N a H_{2} P O_{2}

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Solution

The correct option is B $C a_{3} P_{2} + 6 H_{2} O \to 2 P H_{3} + 3 C a (O H)_{2} a n d C a C_{2} + 2 H_{2} O \to C_{2} H_{2} + C a (O H)_{2}$
When a mixture of calcium carbide and calcium phosphide placed in a container is made to react with water, it produces the gases phosphine and acetylene. This signal produced due to the burning gases is called Holmes signal.
The reactions involved in Holmes signal are:
$C a_{3} P_{2} + 6 H_{2} O \to 2 P H_{3} + 3 C a (O H)_{2} C a C_{2} + 2 H_{2} O \to C_{2} H_{2} + C a (O H)_{2}$

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Similar questions

C a C_{2}

C a_{3} P_{2}

C a C_{2}

C a C_{2}

C a_{3} P_{2}

H_{2} O

C a C_{2} + 2 H_{2} O

⟶

C a (O H)_{2}

C_{2} H_{2}

C a_{3} P_{2} + 6 H_{2} O ⟶ 3 C a (O H)_{2} + 2 P H_{3}

P_{2} H_{4}

C_{2} H_{2}

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