What is the reciprocal sum of the roots for the equation $2 x^{2} + 4 x = 0$ ?

\frac{1}{- 2}

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\frac{1}{2}

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Solution

The correct option is A $\frac{1}{- 2}$
$2 x^{2} + 4 x = 0$
Take $2 x$ common, we get
$2 x (x + 2) = 0$
$2 x = 0, x + 2 = 0$
$x = 0, x = - 2$ are the roots of the equation.
Reciprocal sum of the roots $=$ $\frac{1}{0 - 2}$ = $\frac{1}{- 2}$

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