What is the relation between AM & MB in the given figure?
AM = MB
In the given figure, considering Δs OAM and ΔOBM, we have
OA = OB (Radii of the same circle)
OM = OM (Common Side)
⇒ΔOAM ≅ ΔOBM by RHS criterion of congruency.
⟹AM=MB ( By C.P.C.T)
We know that the perpendicular drawn from the centre of a circle to the chord bisects the chord.
Since OM⊥AB, we have AM=BM.