What is the relation between - H and - E in this reaction-CH4g-2O2g- CO2g-2H2Ol

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Difference between Internal Energy and Enthalpy

What is the r...

Question

What is the relation between $Δ H$ and $Δ E$ in this reaction?
$C H_{4 (g)} + 2 O_{2 (g)} ⇌ C O_{2 (g)} + 2 H_{2} O_{(l)}$

Δ H = Δ E - R T

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Δ H = Δ E - \frac{R T}{2}

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Δ H = Δ E + 2 R T

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Δ H = Δ E - 2 R T

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Δ H

Δ E

C H_{4 (g)} + 2 O_{2 (g)} ⇌ C O_{2 (g)} + 2 H_{2} O_{(l)}

C_{(s)} + O_{2 (g)} \to C O_{2 (g)};

Δ H = - 394 k J

2 H_{2 (g)} + O_{2 (g)} \to 2 H_{2} O_{(l)};

Δ H = - 568 k J

C H_{4 (g)} + 2 O_{2 (g)} \to C O_{2 (g)} + 2 H_{2} O_{(l)};

Δ H = - 394 k J

C H_{4}

C H_{4} (g) + 2 O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l)

Δ H = - 890 k J

1 k g

C H_{4}

Δ E a n d Δ H

{C H}_{3} O H (l)

{C H}_{3} O H (l) + \frac{3}{2} O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l); Δ H = - 726 k J

C (s) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 394 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J

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