Question

What is the self-inductance of a coil when a change of current from 0 to 2 A in 0.05 s induces an emf of 40 V in it?

Answer 1

We know that, $E=L\frac{di}{dt}\Rightarrow 40=L\times \left(\frac{2-0}{0.05}\right)$
$\Rightarrow 40=L\times 40$
$\therefore L=1H$