Question

When the current changes from +2 A to – 2A in 0.05 second, and e.m.f. of 8 V is induced in a coil. The coefficient of self – induction of the coil is

• A. 0.1 H
• B. 0.4 H
• C. 0.04 h
• D. 5 H

Answer 1

The correct option is A 0.1 H

$\begin{array}{c}e=-L\frac{di}{dt}\\ 8=L\frac{\left(4\right)}{0.05}\\ =\frac{8\times 0.05}{4}\\ =0.1\mu \end{array}$