Question

What is the shape of $S{F}_4$?

• A. Square Planar
• B. Trigonal bipyramidal
• C. T-shape
• D. See-saw

Answer 1

The correct option is D See-saw

Lets calculate electron pair of $S{F}_4$

$ep=\frac{(V+L+A-C)}{2}=\frac{(6+4)}{2}=5$

(Central atom $\to$ S, Valence $\to$ 6)

5ep $\Rightarrow$ Trigonal Bipyramidal

Now,

ep = 5 and Ligands = 4 $\Rightarrow$ bp = 4 and lp = 1

Therefore, we can have two structures

because repulsions are less in second structure, it will be more stable.

If we rotate it clockwise ${90}^{\circ }$, it will look like a see-saw.