What is the smallest integer among the given options that satisfies the inequality $4 x + 5 > 2 x - 3$ ?

- 5

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3

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- 3

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4

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5

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Solution

The correct option is C $- 3$
$4 x + 5 > 2 x - 3$

$\Rightarrow$ $2 x + 8 > 0$

so $x > - 4$ and $x$ is an integer
So the smallest integer that satisfies $x$ is " $- 3$ "
Hence, option C is correct.

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Find the number of elements which satisfies the given inequalities.

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\frac{x^{2} - 1}{2 x + 5} < 3

\frac{(x + 2) (x + 3)}{x - 2} \geq 0

4 x - 2 > x - \frac{3 - x}{4} > 3

x

- 3 \leq \frac{4 x - 3}{5} \leq 3

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