Question

What is the speed of electron in the second Bohr's orbit of Hydrogen atom? $(Take{v}_0=2.2\times {10}^{6}m/s)$.

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

The general formula for the speed of electron in Bohr's atomic model is
$v=\frac{Z}{n}{v}_0$
Now, we are talking about second orbit which means n = 2.
And for Hydrogen atom Z=1.
Hence,
$v=\frac{Z}{n}{v}_0=v=\frac{1}{2}{v}_0$
Now, $v_0=2.2\times [10{]}^{6}m/s$
So,
$v=1.1\times {10}^{6}m/s$

Discussion: For previous question try to find out the values for different unknowns and get the solution.