What is the square root of the polynomial using factorisation method: $(16 m^{2} - 24 m + 8)^{2}$ ?

(m - 1) (m - \frac{1}{2})

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∣ ∣ ∣ (m - 1)^{2} (m - \frac{1}{2}) ∣ ∣ ∣

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∣ ∣ ∣ (m - 1) (m - \frac{1}{2}) ∣ ∣ ∣

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∣ ∣ ∣ (m - 1) (m - \frac{1}{2})^{2} ∣ ∣ ∣

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Solution

The correct option is D $∣ ∣ ∣ (m - 1) (m - \frac{1}{2}) ∣ ∣ ∣$
$\sqrt{(16 m^{2} - 24 m + 8)^{2}}$
Factor of $16 m^{2} - 24 m + 8 = (m - 1) (m - \frac{1}{2})$
Therefore, $\sqrt{(16 m^{2} - 24 m + 8)^{2}} = \sqrt{((m - 1) (m - \frac{1}{2}))^{2}}$
$=$ $∣ ∣ ∣ (m - 1) (m - \frac{1}{2}) ∣ ∣ ∣$

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