Question

What is the strength of the electric field such that an electron placed in the field would experience an electrical force equal to its weight?

• A. $5.57\times {10}^{-10}$ N/C
• B. $5.57\times {10}^{-9}$ N/C
• C. $5.57\times {10}^{-8}$ N/C
• D. $5.57\times {10}^{-11}$ N/C

Answer 1

The correct option is D $5.57\times {10}^{-11}$ N/C

qE = mg

$E=\frac{9.1\times {10}^{-31}\times 98}{1.6\times {10}^{19}}=5.57\times {10}^{-11}$ N/C