What is the sum of all the angles of a 9 pointed star $(i . e ., ∠ 1 + ∠ 2 + ∠ 3 + \dots ∠ 8 + ∠ 9)$ :

909^{\circ}

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900^{\circ}

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720^{\circ}

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540^{\circ}

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Solution

The correct option is B $900^{\circ}$

$9 \times 180 - 2 \times 360 = 180 \times 5 = 900^{\circ} ∵ {\begin{matrix} n \times 180 - 2 \times 360 = 180 (n - 4) \end{matrix}}$

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Similar questions

\frac{1}{(\sqrt{1} + \sqrt{2})} + \frac{1}{(\sqrt{2} + \sqrt{3})} + . . . . + \frac{1}{(\sqrt{8} + \sqrt{9})}

\frac{2}{9} \times 3 = \frac{2}{9} \times \frac{3}{1} = \frac{2 \times 3}{9 \times 1} = \frac{6}{9} = \frac{2}{3}

9^{1} + 9^{2} + 9^{3} + . . . . + 9^{8}

N = (323232....... 50

)_{9}

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