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Standard XII

Chemistry

Ideal Gas Equation

What is the s...

Question

What is the surface area ( $m^{2}$ ) of settling tank used for design discharge of $1.5 m^{3} / s ?$ (Assume depth overflow rate for tank as $40 m^{3} / m^{2} / d a y)$

5076.13

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3240.44

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4525.33

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2045.32

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Solution

The correct option is B 3240.44
Given,
$D e s i g n d i s c h a r g e Q = 1.5 m^{3} / s e c$
$O v e r f l o w R a t e = 40 m^{3} / m^{2} / d a y$
As we know
$O v e r f l o w R a t e = \frac{Discharge}{Surface area of tank}$
$S u r f a c e a r e a o f t a n k = \frac{1.5 m^{3} m^{2}}{40 s e c m^{3}} d a y = \frac{1.5}{40} \times 24 \times 60 \times 60 m^{2} = 3240 m^{2}$

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What is the surface area (m2) of settling tank used for design discharge of 1.5m3/s? (Assume depth overflow rate for tank as 40 m3/m2/day)

The correct option is B 3240.44Given, Design discharge Q= 1.5 m3/sec Overflow Rate= 40 m3/m2/day As we know Overflow Rate =DischargeSurface area of tank Surface area of tank=1.5 m3 m240 sec m3day=1.540×24×60×60 m2=3240 m2

What is the surface area ( $m^{2}$ ) of settling tank used for design discharge of $1.5 m^{3} / s ?$ (Assume depth overflow rate for tank as $40 m^{3} / m^{2} / d a y)$