What is the total number of graduates who appeared for both CS and ES together in the year 2009?

66300

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64200

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60800

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62800

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66800

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Solution

The correct option is A 66300
Total number of graduates who appeared for both CS and ES together in the year 2009 $= (65 % o f 70000 + 40$
$= (\frac{65}{100} \times 70000 + \frac{40}{100} \times 52000) = (45500 + 20800) = 66300$

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What is the total number of graduates who appeared for both CS and ES together in the year 2009?

The correct option is A 66300Total number of graduates who appeared for both CS and ES together in the year 2009 =(65% of 70000+40 =(65100×70000+40100×52000)=(45500+20800)=66300

The correct option is A 66300
Total number of graduates who appeared for both CS and ES together in the year 2009 $= (65 % o f 70000 + 40$
$= (\frac{65}{100} \times 70000 + \frac{40}{100} \times 52000) = (45500 + 20800) = 66300$