What is the trend of the atomic radii of the given elements which belong to the second period?

N > C > B

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N > B > C

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B > N > C

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B > C > N

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Solution

The correct option is D
B > C > N

The atomic radius of the elements decreases on moving from left to right in the Modern Periodic Table. The nuclear charge increases across the period which tends to pull the electrons closer to the nucleus due to which the atomic radius decreases across the period

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∣ ∣ ∣ ∣ ∣ \begin{matrix} a + b + n c & (n - 1) a & (n - 1) b (n - 1) c & b + c + n a & (n - 1) b (n - 1) c & (n - 1) a & (c + a + n b) \end{matrix} ∣ ∣ ∣ ∣ ∣

n (A \cap B) = 3, n (B \cap C) = 6, n (A \cap C) = 5 a n d n (A \cap B \cap C) = 2

n [A \cup B \cup C] =

The elements and their atomic numbers are given:

A = 6
B = 24
C = 32
D = 49
Which of the elements belong to same group?

n (S)

n (A \cup B \cup C) = 40, n (A \cap B^{'} \cap C^{'}) = 5, n (B \cap A^{'} \cap C^{'}) = 10, n (C \cap B^{'} \cap A^{'}) = 6

n (A \cap B) = 7 n (B \cap C) = 6, n (A \cap C) = 5

n (A \cap B \cap C) = 2

u (A \cup B \cup C)

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