Question

What is the value of ax${}^2$ + bx + c at x = $\frac{-b}{a}$ ?

• A. $0$
• B. $c$
• C. $a$
• D. None of these

Answer 1

The correct option is B $c$

$a{x}^2+bx+c$

at $x=\frac{-b}{a}$

$a{\left(\frac{-b}{a}\right)}^2$ + b$\left(\frac{-b}{a}\right)+c$

$=c$