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Question

What is the value of k if (k,5) is the solution of the simultaneous equations 4x+3y=19 and 4x−3y=−11?

A
4
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B
1/3
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C
5
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D
1
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Solution

The correct option is D 1
Since, (k,5) is the solution of simultaneous equation.
Therefore, it should satisfy the given equations.
4(k)+3(5)=19
4k=4
k=1

Also,
4k3(5)=11
4k=4
k=1

Therefore, the value of k=1

Hence, this is the answer.

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