What is the value of $sin 15^{o}$ ?

\frac{\sqrt{3} - 1}{2 \sqrt{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{\sqrt{3} + 1}{2 \sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\sqrt{3} - 1}{\sqrt{3} + 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\sqrt{3} + 1}{\sqrt{3} - 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{\sqrt{3} - 1}{2 \sqrt{2}}$
$sin 15^{o} = sin (60^{o} - 45^{o}) = sin 60^{o} cos 45^{o} - cos 60^{o} sin 45^{o} = \frac{\sqrt{3}}{2} \frac{1}{\sqrt{2}} - \frac{1}{2} \frac{1}{\sqrt{2}} = \frac{\sqrt{3} - 1}{2 \sqrt{2}}$

Suggest Corrections

Similar questions

Q. Prove that :

s i n 15^{o} = \frac{\sqrt{3} - 1}{2 \sqrt{2}}

What is the value of $(\frac{2 + \sqrt{3}}{2 - \sqrt{3}} + \frac{2 - \sqrt{3}}{2 + \sqrt{3}} + \frac{\sqrt{3} - 1}{\sqrt{3} + 1})$ ?

Q. What is the value of

\frac{1}{1 + \sqrt{2} + \sqrt{3}} + \frac{1}{1 - \sqrt{2} + \sqrt{3}}

Q. Find the value of

\frac{1}{1 + \frac{1}{3 - \frac{4}{2 + \frac{1}{3 - (\frac{1}{2})}}}} + \frac{3}{3 - \frac{4}{3 + \frac{1}{2 - (\frac{1}{2})}}}

If $a_{1} + 2 a_{2} + 3 a_{3} = 1$ , where $a_{1}, a_{2} & a_{3}$ are all positive numbers; then what is the minimum value of $2^{a 1} + 4^{a 2} + 8^{a 3}$ ?

Join BYJU'S Learning Program

What is the value of sin15o?

The correct option is A √3−12√2sin15o=sin(60o−45o)=sin60ocos45o−cos60osin45o=√321√2−121√2=√3−12√2

What is the value of $sin 15^{o}$ ?

The correct option is A $\frac{\sqrt{3} - 1}{2 \sqrt{2}}$
$sin 15^{o} = sin (60^{o} - 45^{o}) = sin 60^{o} cos 45^{o} - cos 60^{o} sin 45^{o} = \frac{\sqrt{3}}{2} \frac{1}{\sqrt{2}} - \frac{1}{2} \frac{1}{\sqrt{2}} = \frac{\sqrt{3} - 1}{2 \sqrt{2}}$