Question

What is the value of $\sqrt[3]{3-8}-\sqrt[3]{3-216}$ ?

• A. 4
• B. -8
• C. -4
• D. 8

Answer 1

The correct option is A

4

- 8 = - $2\times -2\times -2$

$\sqrt[3]{3-8}=-2$

- 216 = $-6\times -6\times -6$

$\sqrt[3]{3-216}=-6$

So the given expression $\sqrt[3]{3-8}-\sqrt[3]{3-216}$ becomes - 2 - (- 6) = - 2 + 6

= 4