wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the value of van’t Hoff factor (i) for 60% association of CH3COOH in benzene?

A
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.7
In benzene, two molecules of ethanoic acid associate to form a dimer.
2CH3COOH(CH3COOH)2
Initial a 0At.eq a(1α) aα2
Number of moles at eq. neq=a(1α+α/2)
At 60 % association α=0.6
neq=a(10.6+0.3)=a(0.7)

van't Hoff factor i = number of solute particles in solutiontheoritical number of solute particles
i=a(0.7)a=0.7

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Van't Hoff Factor
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon