Question

what is the value of x =
x/square of 98=square root of 392/x

Answer 1

Dear student,

$$\begin{gathered} \frac{\mathrm{x}}{\sqrt{98}}=\frac{\sqrt{392}}{\mathrm{x}} \\ \Rightarrow {\mathrm{x}}^2=\sqrt{392}\times \sqrt{98} \\ \Rightarrow {\mathrm{x}}^2=\sqrt{392\times 98} \\ \Rightarrow {\mathrm{x}}^2=\sqrt{2\times 2\times 98\times 98} \\ \Rightarrow {\mathrm{x}}^2=2\times 98 \\ \Rightarrow {\mathrm{x}}^2=196 \\ \Rightarrow \mathrm{x}=\sqrt{196} \\ \Rightarrow \mathrm{x}=14 \end{gathered}$$
Regards