Suppose the initial velocity, u, makes an angle of θ with the horizontal. When the velocity is perpendicular to initial velocity, it makes an angle of (90-θ) with the horizontal.
Since there is no acceleration in horizontal, horizontal velocity component will remain the same:
ucosθ = vcos(90-θ)
ucosθ = vsinθ
v= ucotθ
Hence, velocity of projectile when it moves perpendicular to initial velocity is ucotθ where u is the initial velocity.