Question

What is the volume at STP of 10 L of gas initially at 546 K and 2 atm ?

• A. 5 L
• B. 10 L
• C. 15 L
• D. 20 L
• E. 25 L

Answer 1

The correct option is B 10 L

Number of moles of gas are same in both states.

So using ideal gas law,

$P_1{V}_1$$=$$n_{1}R{T}_1$ and $P_2{V}_2$$=$$n_{2}R{T}_2$

and $n_1$$=$$n_2$,

$P_1{V}_1$/$T_1$ $=$ $P_2{V}_2$/$T_2$

At STP , $P_1$$=$1 atm $T_1$$=$$273K$

$1\times V_1$/$273$$=$$2\times 10/546$

$\therefore V_1$$=$$10$L