Question

What is the volume (in L) of a 2 M $HCl$ solution if it contains 365 g of $HCl$?

Answer 1

$\text{Number of moles of}HCl=\frac{\text{given mass of}HCl}{\text{molar mass}}$
$=\frac{365}{36.5}=10$

$\text{Molarity}=\frac{\text{number of moles of solute}}{\text{volume of solution in mL}}\times 1000$

$\Rightarrow 2=\frac{10}{\text{volume of solution in mL}}\times 1000$

On solving, volume of the $HCl$ solution is 5000 mL or 5 L.