What is the volume of "20 volume $H_{2} O_{2}$ " required to get $5000 c m^{3}$ of oxygen at S.T.P?

250 c m^{3}

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50 c m^{3}

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100 c m^{3}

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125 c m^{3}

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Solution

The correct option is A $250 c m^{3}$
$5000 c m^{3}$ of oxygen corresponds to 5 L.
20 volume $H_{2} O_{2}$ means that decomposition of 1 L of $H_{2} O_{2}$ gives 20 L of oxygen at STP.

5 L of oxygen at S.T.P will be obtained from decomposition of $\frac{5}{20} \times 1 = 0.250 L H_{2} O_{2}$ .

This corresponds to $250 c m^{3}$ of 20 volume $H_{2} O_{2}$ .

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