What is the volume of any gas at NTP. Find it using the ideal gas law

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$D e a r S t u d e n t V o l u m e o f a n y g a s a t N T P i s 22.4 L A t N T P, P = 1 a t m a n d T = 20 ° C = 293 K, R = 0.0821 L a t m K^{- 1} m o l^{- 1} P V = R T (f o r 1 m o l e g a s) V = \frac{R T}{P} = \frac{0.0821 \times 293}{1} = 24.13 L C o n s i d e r i t a s 22.4 L f o r b o t h S T P a n d N T P, w h i c h i s a c c o r d i n g t o I U P A C . R e g a r d s$

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What is the volume of any gas at NTP. Find it using the ideal gas law

Dear StudentVolume of any gas at NTP is 22.4 LAt NTP, P=1 atm and T=20°C=293 K, R=0.0821L atm K-1mol-1PV=RT (for 1 mole gas)V=RTP=0.0821×2931=24.13 LConsider it as 22.4 L for both STP and NTP, which is according to IUPAC.Regards