Question

What is the volume of $O_2$ liberated at anode at STP in the electrolysis of $CdS{O}_4$ solution when a current of 2 A is passed for 8 min?

Answer 1

$v=2A$ , $t=480sec$

$Q=i.t=(2\times 480)coulomb$

Number of faraday $=\left(\frac{960}{96500}\right)=9.94\times {10}^{-3}F$

Since 1F produces 5.6litre of $O_2$ at STP

$\therefore 9.94\times {15}^{3}F$ produces $(5.6\times 9.94\times {10}^{-3})$ litre

$=0.056litre$