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Bromine Water Test

What is the w...

Question

What is the weight of bromine needed for the reaction with 21 gm of $C_{3} H_{6}$ ?
(atomic weight of Br =80)

40 g

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80 g

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160 g

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120 g

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Solution

The correct option is B 80 g
$C_{3} H_{6} + B r_{2} \to C_{3} H_{6} B r_{2}$
42gm of $C_{3} H_{6}$ needs 160 gm of bromine
1gm of $C_{3} H_{6}$ needs $160 / 42$
So, 21 gm of $C_{3} H_{6}$ needs $\frac{160}{42} \times 21$
$= 80 g m$ of bromine

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