What is the weight of oxygen required for the complete combustion of $2.8 k g$ of ethylene?

2.8 k g

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6.4 k g

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9.6 k g

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96 k g

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Solution

The correct option is D $6.4 k g$
$C_{2} H_{4} + 2 O_{2} \to 2 C O_{2} + 2 H_{2} O$

$∵ 28 g m C_{2} H_{4}$ requires $64 g m$ oxygen

$∴ 2.8 \times 10^{3} g m C_{2} H_{4}$ requires $= \frac{64}{28} \times 2.8 \times 10^{3} g m$

$= 6.4 \times 10^{3} g m = 6.4 k g .$

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What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene

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