What is the weight of oxygen that is required for the complete combustion of 2.8 kg of ethylene ?

9.6 kg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

96.0 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.4 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.8 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 9.6 kg
$C_{2} H_{4} (12 \times 2 + 4) + 3 O_{2} 96 k g \to 2 C O_{2} + 2 H_{2}$

$= 28 k g$

$∵$ Weight of oxygen required for the Complete combustion of 28 kg ethylene = 96 kg

$∵$ Weight of oxygen required for the combustion of 2.8 kg ethylene.

$= \frac{96 \times 2.8}{28} = 9.6 k g$

Hence, the correct option is $A$

Suggest Corrections

Similar questions

2.8 k g

What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene

12 m l

54 m l

200 c m^{3}

C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O

Join BYJU'S Learning Program