What is the work done by the force of tension in lifting mass m a distance h ?

\frac{2 m M g h}{m + M}

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\frac{(M - m) g h}{m + M}

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\frac{m M g h}{m + M}

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\frac{M g h}{m + M}

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Solution

The correct option is C $\frac{2 m M g h}{m + M}$
Using the equations
$M g - T = M a$
and $T - m g = m a$

$T = \frac{2 M m g}{M + m}$
Hence the work done in lifting mass $m$ by $h = T h = \frac{2 M m g h}{M + m}$

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What is the work done by the force of tension in lifting mass m a distance h ?

The correct option is C 2mMghm+MUsing the equations Mg−T=Maand T−mg=maT=2MmgM+mHence the work done in lifting mass m by h=Th=2MmghM+m

The correct option is C $\frac{2 m M g h}{m + M}$
Using the equations
$M g - T = M a$
and $T - m g = m a$

$T = \frac{2 M m g}{M + m}$
Hence the work done in lifting mass $m$ by $h = T h = \frac{2 M m g h}{M + m}$