What is Z in the following reaction?
${C H}_{3} - {C H}_{2} - {C O}_{2}^{⊖} {N a}^{\oplus} Δ - ------ \to N a O H / C a O Z$

Propane

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N-butane

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Ethane

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Ethyne

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Solution

The correct option is C Ethane
When sodium salt of carboxylic acid is heated with soda lime, an alkane is obtained.
${C H}_{3} - {C H}_{2} - {C O}_{2}^{⊖} {N a}^{\oplus} Δ - ------ \to N a O H / C a O C H_{3} - C H_{3} Z + N a_{2} C O_{3}$
Hence, the compound Z is ethane
$C H_{3} - C H_{3}$
Note: The product alkane contains one C atom less than the reactant (sodium salt of carboxylic acid).

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