What length of a wire of specific resistance 2- 10 -6 - m and cross-sectional area 5 should be taken to form a coil of resistance 10-

The correct option is C 25m Given, A=5mm^2=5× 10^ 6m^2 ρ=2× 10^ 6Ω m R=10Ω The resistance of the wire is given by R=ρlA l=RAρ l ...

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Standard XII

Physics

Ohm's Law in Scalar Form

What length o...

Question

What length of a wire of specific resistance $2 \times 10^{- 6} Ω m$ and cross-sectional area $5$ should be taken to form a coil of resistance $10 Ω$ .

10 m

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15 m

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25 m

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20 m

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Solution

The correct option is C $25 m$
Given,
$A = 5 m m^{2} = 5 \times 10^{- 6} m^{2}$
$ρ = 2 \times 10^{- 6} Ω m$
$R = 10 Ω$
The resistance of the wire is given by
$R = ρ \frac{l}{A}$
$l = \frac{R A}{ρ}$
$l = \frac{10 \times 5 \times 10^{- 6}}{2 \times 10^{- 6}} = 25 m$
The correct option is C.

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What length of a wire of specific resistance 2×10−6Ωm and cross-sectional area 5 should be taken to form a coil of resistance 10Ω.

The correct option is C 25mGiven,A=5mm2=5×10−6m2ρ=2×10−6ΩmR=10ΩThe resistance of the wire is given byR=ρlAl=RAρl=10×5×10−62×10−6=25mThe correct option is C.

What length of a wire of specific resistance $2 \times 10^{- 6} Ω m$ and cross-sectional area $5$ should be taken to form a coil of resistance $10 Ω$ .

The correct option is C $25 m$
Given,
$A = 5 m m^{2} = 5 \times 10^{- 6} m^{2}$
$ρ = 2 \times 10^{- 6} Ω m$
$R = 10 Ω$
The resistance of the wire is given by
$R = ρ \frac{l}{A}$
$l = \frac{R A}{ρ}$
$l = \frac{10 \times 5 \times 10^{- 6}}{2 \times 10^{- 6}} = 25 m$
The correct option is C.