Question

What mass of ${}_{92}^{235}\text{U}$ has to undergo fission each day to provide $3000$ $MW$ of power each day ?

• A. $3.2$ $g$
• B. $320$ $g$
• C. $3.2$ $kg$
• D. $32$ $kg$

Answer 1

The correct option is C $3.2$ $kg$

$1$ fission or $235$ $U$ gives $200$ $MeV$

$\frac{m\times 200\times 1.6\times {10}^{-13}}{235\times 1.66\times {10}^{-27}}={10}^6\times 3000\times 86400$

$m$ = $3.2$ $kg$