Question

What mass of calcium chloride should be added to 300 ml of water to prepare 2.46 m solution?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Let mass of $CaC{l}_2=x$
Mass of water = volume of water $\times$ density = 300 ml $\times$ $\frac{1g}{ml}=300g$
$m=\frac{\text{no.of mass of solute}}{\text{mass of solvent(g)}}\times 1000$
$=\frac{\left(\frac{x}{111}\right)}{300}\times 1000=81.9g$