You visited us 1 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

What mass of ...

Question

What mass of glucose is required to produce $88 g$ of $C O_{2}$ on complete combustion?

30 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

22 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $60 g$
$C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O$
Gram molar mass of $C_{6} H_{12} O_{6} = (6 \times 12) + (12 \times 1) + (6 \times 16) = 180 g$
Now,
$(6 \times 44) g$ of $C O_{2}$ is produced by $180 g$ of glucose.
So, $88 g$ of $C O_{2}$ is produced by $(\frac{180}{6 \times 44} \times 88) = 60 g$ of glucose.

Suggest Corrections

Similar questions

What is the mass of glucose required to produce 44g of CO₂

on complete combustion?

88 g

C O_{2}

A g_{2} C O_{3} (s)

C_{2} H_{2}

11.2 L

C O_{2}

A g = 108 g/mol

A g_{2} C O_{3 (s)} \to 2 A g_{(s)} + C O_{2 (g)} + \frac{1}{2} O_{2 (g)}

C_{2} H_{2} + \frac{5}{2} O_{2} \to 2 C O_{2} + H_{2} O

44

C = 12

H = 1

O = 16

A g_{2} C O_{3} (s)

C_{2} H_{2}

11.2 L

C O_{2}

A g = 108 g/mol

A g_{2} C O_{3 (s)} \to 2 A g_{(s)} + C O_{2 (g)} + \frac{1}{2} O_{2 (g)}

C_{2} H_{2} + \frac{5}{2} O_{2} \to 2 C O_{2} + H_{2} O

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program