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Stoichiometric Calculations

What mass of ...

Question

What mass of glucose is required to produce $88 g$ of $C O_{2}$ on complete combustion?

A

30 g

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B

45 g

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C

60 g

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D

22 g

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Solution

The correct option is C $60 g$
$C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O$
Gram molar mass of $C_{6} H_{12} O_{6} = (6 \times 12) + (12 \times 1) + (6 \times 16) = 180 g$
Now,
$(6 \times 44) g$ of $C O_{2}$ is produced by $180 g$ of glucose.
So, $88 g$ of $C O_{2}$ is produced by $(\frac{180}{6 \times 44} \times 88) = 60 g$ of glucose.

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