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Stoichiometric Calculations

What mass of ...

Question

What mass of $H N O_{3}$ is needed to convert 5 g of iodine into iodic acid according to the reaction?
$I_{2} + H N O_{3} \to H P O_{3} + N O_{2} + H_{2} O$

1.24 g

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24.8 g

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0.248 g

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49.6 g

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Solution

The correct option is A 1.24 g
according to the equation,
1 mole of $H N O_{3}$ require 1 mole of $I_{2}$
so, no. of moles of $H N O_{3}$ = no. of moles of $I_{2}$
$\frac{m a s s o f H N O_{3}}{m o l e c u l a r m a s s}$ = $\frac{m a s s o f I_{2}}{m o l e c u l a r m a s s}$

$\frac{m a s s o f H N O_{3}}{63}$ = $\frac{5}{253.8}$

mass of $H N O_{3}$ = 1.24 g

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Similar questions

H N O_{3}

5 g

I_{2} + H N O_{3} ⟶ H I O_{3} + N O_{2} + H_{2} O

What mass of $H N O_{3}$ is needed to convert 5 g of iodine into iodic acid according to the reaction? (at mass of I = 127 u)

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\Rightarrow

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