What must be added to the sum of $2 a^{2} - 3 a + 7, - 5 a^{2} - 2 a - 11$ and $3 a^{2} + 5 a - 8$ to get $0$ ?

- 12

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12

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a^{2} + a

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a - 1

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Solution

The correct option is A $12$
Let ' $x$ ' be added to these polynomial to get $0$ .
$\Rightarrow (2 a^{2} - 3 a + 7) + (- 5 a^{2} - 2 a - 11) + (3 a^{2} + 5 a - 8) + x = 0$
$\Rightarrow (2 a^{2} - 5 a^{2} + 3 a^{2}) + (- 3 a - 2 a + 5 a) + (7 - 11 - 8) + x = 0$
$\Rightarrow 0 + 0 + (- 12) + x = 0$
$\Rightarrow x = 12$
Option B is correct.

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