What must be subtracted from the polynomial p(x)=x4+2x3-13x2-12x+21 so that the resulting polynomial is exactly divisible by x2-4x+3?
Step 1: Division
Letx2-4x+3x2+6x+8x4+2x3-13x2-12x+21
x4-4x3+3x26x3-16x2-12x
6x3-24x2+18x8x2-30x+21
8x2-32x+242x-3
Step 2: Subtracting the remainder
Inordertodividethep(x)byx2-4x+3wesubtracttheremainderr(x)=2x-3top(x)i.e.,x4+2x3-13x2-12x-21-2x-3=x4+2x3-13x2-14x+24NowforVerification:
x2-4x+3x2+6x+8x4+2x3-13x2-14x+24
x4-4x3+3x26x3-16x2-14x
6x3-24x2+18x8x2-32x+24
8x2-32x+240Hence verified
Therefore, the subtracted polynomial is 2x-3
Write the face value and place value of the digits shown in colour.
340671
b) 257208
What must be subtracted from polynomial f(x)=x4+2x3−13x2−12x+21 so that the resulting polynomial is exactly divisible by x2−4x+3 ?
Divide 3x3+5x2+2x+7byx2+2x+3,find the quotient and remainder and verify the division algorithm.
Find all the zeroes of 2x4-3x3-3x2+6x-2, if two of its zeroes are 2 and -2.